Vektor a=2i+i-2k, b=i-3i, c=2j+k tentukan a=(b+c)

Pertanyaan:

Vektor a=2i+i-2k, b=i-3i, c=2j+k tentukan a=(b+c)

Langkah-langkah Penyelesaian Vektor a ⃗ modifying-above a with right arrow a ⃗ , b ⃗ modifying-above b with right arrow b ⃗ , dan c ⃗ modifying-above c with right arrow c ⃗ dituliskan dalam bentuk komponen. a ⃗ = 2 i ̂ + j ̂ − 2 k ̂ modifying-above a with right arrow equals 2 i hat plus j hat minus 2 k hat a ⃗ = 2 i ̂ + j ̂ − 2 k ̂ b ⃗ = i ̂ − 3 j ̂ modifying-above b with right arrow equals i hat minus 3 j hat b ⃗ = i ̂ − 3 j ̂ c ⃗ = 2 j ̂ + k ̂ modifying-above c with right arrow equals 2 j hat plus k hat c ⃗ = 2 j ̂ + k ̂ Vektor b ⃗ modifying-above b with right arrow b ⃗ dan c ⃗ modifying-above c with right arrow c ⃗ dijumlahkan. b ⃗ + c ⃗ = ( i ̂ − 3 j ̂ ) + ( 2 j ̂ + k ̂ ) modifying-above b with right arrow plus modifying-above c with right arrow equals open paren i hat minus 3 j hat close paren plus open paren 2 j hat plus k hat close paren b ⃗ + c ⃗ = ( i ̂ − 3 j ̂ ) + ( 2 j ̂ + k ̂ ) b ⃗ + c ⃗ = i ̂ + ( -3 + 2 ) j ̂ + k ̂ modifying-above b with right arrow plus modifying-above c with right arrow equals i hat plus open paren negative 3 plus 2 close paren j hat plus k hat b ⃗ + c ⃗ = i ̂ + ( − 3 + 2 ) j ̂ + k ̂ b ⃗ + c ⃗ = i ̂ − j ̂ + k ̂ modifying-above b with right arrow plus modifying-above c with right arrow equals i hat minus j hat plus k hat b ⃗ + c ⃗ = i ̂ − j ̂ + k ̂ Hasil perkalian titik (dot product) antara vektor a ⃗ modifying-above a with right arrow a ⃗ dan ( b ⃗ + c ⃗ ) open paren modifying-above b with right arrow plus modifying-above c with right arrow close paren ( b ⃗ + c ⃗ ) dihitung. a ⃗ ⋅ ( b ⃗ + c ⃗ ) = ( 2 i ̂ + j ̂ − 2 k ̂ ) ⋅ ( i ̂ − j ̂ + k ̂ ) modifying-above a with right arrow center dot open paren modifying-above b with right arrow plus modifying-above c with right arrow close paren equals open paren 2 i hat plus j hat minus 2 k hat close paren center dot open paren i hat minus j hat plus k hat close paren a ⃗ ⋅ ( b ⃗ + c ⃗ ) = ( 2 i ̂ + j ̂ − 2 k ̂ ) ⋅ ( i ̂ − j ̂ + k ̂ ) a ⃗ ⋅ ( b ⃗ + c ⃗ ) = ( 2 ) ( 1 ) + ( 1 ) ( -1 ) + ( -2 ) ( 1 ) modifying-above a with right arrow center dot open paren modifying-above b with right arrow plus modifying-above c with right arrow close paren equals open paren 2 close paren open paren 1 close paren plus open paren 1 close paren open paren negative 1 close paren plus open paren negative 2 close paren open paren 1 close paren a ⃗ ⋅ ( b ⃗ + c ⃗ ) = ( 2 ) ( 1 ) + ( 1 ) ( − 1 ) + ( − 2 ) ( 1 ) a ⃗ ⋅ ( b ⃗ + c ⃗ ) = 2 − 1 − 2 modifying-above a with right arrow center dot open paren modifying-above b with right arrow plus modifying-above c with right arrow close paren equals 2 minus 1 minus 2 a ⃗ ⋅ ( b ⃗ + c ⃗ ) = 2 − 1 − 2 a ⃗ ⋅ ( b ⃗ + c ⃗ ) = -1 modifying-above a with right arrow center dot open paren modifying-above b with right arrow plus modifying-above c with right arrow close paren equals negative 1 a ⃗ ⋅ ( b ⃗ + c ⃗ ) = − 1 Jawaban Akhir Hasil dari a ⃗ ⋅ ( b ⃗ + c ⃗ ) modifying-above a with right arrow center dot open paren modifying-above b with right arrow plus modifying-above c with right arrow close paren a ⃗ ⋅ ( b ⃗ + c ⃗ ) adalah -1 negative 1 − 1 . Link Terkait